-3x^2+26x+35=0

Solution for -3x^2+26x+35=0 equation:

-3x^2+26x+35=0

a = -3; b = 26; c = +35;
Δ = b2-4ac
Δ = 262-4·(-3)·35
Δ = 1096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1096}=\sqrt{4*274}=\sqrt{4}*\sqrt{274}=2\sqrt{274}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{274}}{2*-3}=\frac{-26-2\sqrt{274}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{274}}{2*-3}=\frac{-26+2\sqrt{274}}{-6}
$